Question

Question: 2In a hydrogen atom, an electron revolves at velocity 2.2 X 10^6 m/s. Calculate the magnetflux density at the center of the electron's orbit. Assume that the radius pf the orbit is R=53x 10^-11m.​

Answer 1

Answer:

Answer!

do like and rate!

so what happens basically is we know that

$b = mu \div 4\pi \: \times i \times dl \: \sin(x) \div {r}^{2}$

now I.dl can be written as dq/dt.dl and dl/dt is velocity so,

$i \times dl = dq \times velocity$

therefore,

$b = mu \div 4\pi \: \times q \times v \times r \div {r}^{3}$

using the values and evaluating them gives

B= 50.12 T or

$wb \div {m}^{2}$