Question 3
1 Marks
If one zero of the quadratic polynomial x2 + 3x + k is 2, then value of k
Answers
The value of k is -10
The value of k is -10 Step-by-step explanation:
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we get
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2 +3(2)+k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2 +3(2)+k0=4+6+k0=4+6+k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2 +3(2)+k0=4+6+k0=4+6+k0=10+k0=10+k
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2 +3(2)+k0=4+6+k0=4+6+k0=10+k0=10+kk=-10k=−10
The value of k is -10 Step-by-step explanation:Given : Quadratic polynomial x^2+3x+kx 2 +3x+kOne of the root is 2To find : The value of kSolution :Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x 2 +3x+kGiven one of the zero of the quadratic polynomial is 2.Hence f(2) = 0Put x = 2 in f(x), we getf(2)=2^2+3(2)+kf(2)=2 2 +3(2)+k0=4+6+k0=4+6+k0=10+k0=10+kk=-10k=−10Therefore, The value of k is -10.