Chemistry, asked by Rajput2stars, 9 months ago

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ⁱⁿ ᵗʰᵉ ᵖʳᵉˢᵉⁿᶜᵉ ᵒᶠ ᶜⁿ, (ᵃ ˢᵗʳᵒⁿᵍ ˡⁱᵍᵃⁿᵈ) ᵗʰᵉ 3ᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ ᵖᵃⁱʳ ᵘᵖ ˡᵉᵃᵛⁱⁿᵍ ᵒⁿˡʸ ᵒⁿᵉ ᵘⁿᵖᵃⁱʳᵉᵈ ᵉˡᵉᶜᵗʳᵒⁿ. ᵗʰᵉ ʰʸᵇʳⁱᵈⁱˢᵃᵗⁱᵒⁿ ⁱˢ ᵈ² ˢᵖ³ ᶠᵒʳᵐⁱⁿᵍ ⁱⁿⁿᵉʳ ᵒʳᵇⁱᵗᵃˡ ᶜᵒᵐᵖˡᵉˣ. ⁱⁿ ᵗʰᵉ ᵖᵉʳˢᵉⁿᶜᵉ ᵒᶠ ʰ2ᵒ, (ᵃ ʷᵉᵃᵏ ˡⁱᵍᵃⁿᵈ), 3ᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ ᵈᵒ ⁿᵒᵗ ᵖᵃⁱʳ ᵘᵖ. ᵗʰᵉ ʰʸᵇʳⁱᵈⁱˢᵃᵗⁱᵒⁿ ⁱˢ ˢᵖ³ ᵈ³ ᶠᵒʳᵐⁱⁿᵍ ᵃⁿ ᵒᵘᵗᵉʳ ᶜᵒᵐᵖˡᵉˣ ᶜᵒⁿᵗᵃⁱⁿⁱⁿᵍ ᶠⁱᵛᵉ ᵘⁿᵖᵃⁱʳᵉᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ, ⁱᵗ ⁱˢ ˢᵗʳᵒⁿᵍˡʸ ᵖᵃʳᵃᵐᵃᵍⁿᵉᵗⁱᶜ.ⁱⁿ ᵗʰᵉ ᵖʳᵉˢᵉⁿᶜᵉ ᵒᶠ ᶜⁿ, (ᵃ ˢᵗʳᵒⁿᵍ ˡⁱᵍᵃⁿᵈ) ᵗʰᵉ 3ᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ ᵖᵃⁱʳ ᵘᵖ ˡᵉᵃᵛⁱⁿᵍ ᵒⁿˡʸ ᵒⁿᵉ ᵘⁿᵖᵃⁱʳᵉᵈ ᵉˡᵉᶜᵗʳᵒⁿ. ᵗʰᵉ ʰʸᵇʳⁱᵈⁱˢᵃᵗⁱᵒⁿ ⁱˢ ᵈ² ˢᵖ³ ᶠᵒʳᵐⁱⁿᵍ ⁱⁿⁿᵉʳ ᵒʳᵇⁱᵗᵃˡ ᶜᵒᵐᵖˡᵉˣ. ⁱⁿ ᵗʰᵉ ᵖᵉʳˢᵉⁿᶜᵉ ᵒᶠ ʰ2ᵒ, (ᵃ ʷᵉᵃᵏ ˡⁱᵍᵃⁿᵈ), 3ᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ ᵈᵒ ⁿᵒᵗ ᵖᵃⁱʳ ᵘᵖ. ᵗʰᵉ ʰʸᵇʳⁱᵈⁱˢᵃᵗⁱᵒⁿ ⁱˢ ˢᵖ³ ᵈ³ ᶠᵒʳᵐⁱⁿᵍ ᵃⁿ ᵒᵘᵗᵉʳ ᶜᵒᵐᵖˡᵉˣ ᶜᵒⁿᵗᵃⁱⁿⁱⁿᵍ ᶠⁱᵛᵉ ᵘⁿᵖᵃⁱʳᵉᵈ ᵉˡᵉᶜᵗʳᵒⁿˢ, ⁱᵗ ⁱˢ ˢᵗʳᵒⁿᵍˡʸ ᵖᵃʳᵃᵐᵃᵍⁿᵉᵗⁱᶜ.​

Answers

Answered by aman7913
2

HERE YOUR ANSWER:

[Fe(H2O)6]^-2 is strongly paramagnetic where [Fe(CN)6]^-3 is weakly paramagnetic.

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hope it helps you

Answered by MsAainaDz
0

Explanation:

[Fe(H2O)6]^-2 is strongly paramagnetic where [Fe(CN)6]^-3 is weakly paramagnetic.

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