Question 3: 2 objects of mass 5 kg and 8 kg are at rest. F1 and F2 are the forces applied on both of them respectively. If the speed of both objects after 10 seconds become 10 m/s and 20 m/s, then find the value of F1 -F2.
using the formula v=u+at
with clear explanation
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Two objects of mass 5 kg and 8 kg at rest F1 and F2 meters force applied on both the boxes respectively If the speed of both the objects after 5 sec become 16m/s and 15m/s respectively find the value of F1 and F2
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Answer:-
Given:
First Object:
Mass (m₁) = 5 kg
Initial Velocity (u₁) = 0 m/s
Final velocity (v₂) = 16 m/s
time = 5 s
We know that,
Force = mass * acceleration
And acceleration = (v - u) / t.
Hence,
F₁ = 5 * (16 - 0) / 5
→ F₁ = 5 * 16/5
→ F₁ = 16 N
Second Object:
Mass (m₂) = 8 kg
Initial Velocity (u₂) = 0 m/s
Final Velocity (v₂) = 15 m/s
Time = 5 s
Hence,
F₂ = 8 * (15 - 0) / 5
→ F₂ = 8 * 15/5
→ F₂ = 24 N
Additional Information:
Force:
It is the push or pull of an Object.
It is a vector quantity.
It is denoted by "F".
F = ma, where m is the Mass of the Object and a is it's acceleration.
It's units are Newtons (N) and dynes (dyn).
It depends on mass & acceleration of the object.
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