Physics, asked by banothsidhu2007, 6 months ago

Question 3.2:
The position-time (x-t) graphs for two children A and B returning from their school O to
their homes P and Q respectively are shown in Fig. 3.19. Choose the correct entries in the
brackets below;
a) (A/B) lives closer to the school than (B/A)
b) (A/B) starts from the school earlier than (B/A)
c) (A/B) walks faster than (B/A)
d) A and B reach home at the (same/different) time
e) (A/B) overtakes (B/A) on the road (once/twice).

Answers

Answered by Chidagni
1

Answer:

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Answered by padmamaloth1986
3

Answer 3.2:

A lives closer to school than B.

A starts from school earlier than B.

A walks faster than A.

A and B reach home at the same time.

A overtakes A once on the road.

Explanation:

In the given x–t graph, it can be observed that distance OP < OQ. Hence, the distance of

school from the A’s home is less than that from B’s home.

In the given graph, it can be observed that for x = 0, t = 0 for A, whereas for x = 0, t has

some finite value for B. Thus, A starts his journey from school earlier than B.

In the given x–t graph, it can be observed that the slope of B is greater than that of A.

Since the slope of the x–t graph gives the speed, a greater slope means that the speed of

B is greater than the speed A.

It is clear from the given graph that both A and B reach their respective homes at the same

time.

B moves later than A and his/her speed is greater than that of A. From the graph, it is

clear that B overtakes A only once on the road. mark brainlist

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