Question - 3
2x-3y +6=0
2x+3y-18=0
solve by substitution method
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Given equations
2x−3y+6=0
2x+3y−18=0
From the graph, the intersection point is (3,4).
The point of intersection with y-axis are (0,2),(0,6).
The length of the base of the triangle with y-axis =4 units
Height =4units
So, Area = 1/2 ×3×4
=6 units
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