Question 3.5: At room temperature (27.0 °C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the material of the resistor is
Class 12 - Physics - Current Electricity Current Electricity Page-127
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we know relation between resistance and temperature . it is given by
here, R is the resistance at temperature T
is the resistance at temperature
is the Coefficient of resistance
Given, R = 117Ω , R₀ = 100Ω , α = 1.7 × 10^-4 /°C and T₀ = 27°C
so, 117 = 100 [ 1 + 1.7 × 10^-4(T - 27)
117 = 100 + 1.7 × 10^-2 (T - 27)
17 = 1.7 × 10^-2(T - 27)
1000 = T - 27
T = 1027°C
hence, temperature of the element if the resistance is found by 117Ω is 1027°C
here, R is the resistance at temperature T
is the resistance at temperature
is the Coefficient of resistance
Given, R = 117Ω , R₀ = 100Ω , α = 1.7 × 10^-4 /°C and T₀ = 27°C
so, 117 = 100 [ 1 + 1.7 × 10^-4(T - 27)
117 = 100 + 1.7 × 10^-2 (T - 27)
17 = 1.7 × 10^-2(T - 27)
1000 = T - 27
T = 1027°C
hence, temperature of the element if the resistance is found by 117Ω is 1027°C
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