Math, asked by devilhere77, 3 months ago

QUESTION 3:- ΔABC is right angled at A (see the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.

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Answers

Answered by Anonymous
10

Step-by-step explanation:

answer is in picture above

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Answered by itzsehaj
11

QUESTION:-

ΔABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.

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GIVEN:-

  • ΔABC is right angled at A
  • AD is perpendicular to BC.
  • AB = 5 cm, BC = 13 cm and AC = 12 cm

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TO FIND:-

  • The area of triangle ABC
  • Length of AD

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ANSWER:-

according to the question,

  • AB = 5 cm
  • BC = 13 cm
  • AC = 12 cm

We know that,

Area of the ΔABC = ½ × base × height

= ½ * AB * AC\\= ½ * 5 * 12\\= 1 * 5 * 6\\= 30 cm2

 Now,

Area of ΔABC = ½ × base × height

30 =  ½ * AD * BC30 \\=  ½ *  AD * 3(30 * 2)\\/13 = ADAD \\= 60/13AD\\ = 4.6 cm

Therefore, area of triangle ABC = 30cm^2  and   length of AD = 4.6cm

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                     hope it helps :D

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