"Question 3 AD and BC are equal perpendiculars to a line segment AB (See the given figure). Show that CD bisects AB.
Class 9 - Math - Triangles Page 119"
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Congruence of triangles:
Two ∆’s are congruent if sides and angles of a triangle are equal to the corresponding sides and angles of the other ∆.
In Congruent Triangles corresponding parts are always equal and we write it in short CPCT i e, corresponding parts of Congruent Triangles.
It is necessary to write a correspondence of vertices correctly for writing the congruence of triangles in symbolic form.
Criteria for congruence of triangles:
There are 4 criteria for congruence of triangles.
ASA(angle side angle):
Two Triangles are congruent if two angles and the included side of One triangle are equal to two angles & the included side of the other triangle.
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Given,
AD and BC are equal perpendiculars to AB.
To prove,
CD bisects AB i.e, OA=OB
Proof,
In ΔAOD and ΔBOC,
∠A = ∠B (Perpendicular)
∠AOD = ∠BOC (Vertically opposite angles)
AD = BC (Given)
Hence, ΔAOD ≅ ΔBOC (by ASA congruence rule.)
Then,
AO = OB (CPCT).
Thus,CD bisects AB.
-----------------------------------------------------------------------------------------------------
Two ∆’s are congruent if sides and angles of a triangle are equal to the corresponding sides and angles of the other ∆.
In Congruent Triangles corresponding parts are always equal and we write it in short CPCT i e, corresponding parts of Congruent Triangles.
It is necessary to write a correspondence of vertices correctly for writing the congruence of triangles in symbolic form.
Criteria for congruence of triangles:
There are 4 criteria for congruence of triangles.
ASA(angle side angle):
Two Triangles are congruent if two angles and the included side of One triangle are equal to two angles & the included side of the other triangle.
---------------------------------------------------------------------------------------------------
Given,
AD and BC are equal perpendiculars to AB.
To prove,
CD bisects AB i.e, OA=OB
Proof,
In ΔAOD and ΔBOC,
∠A = ∠B (Perpendicular)
∠AOD = ∠BOC (Vertically opposite angles)
AD = BC (Given)
Hence, ΔAOD ≅ ΔBOC (by ASA congruence rule.)
Then,
AO = OB (CPCT).
Thus,CD bisects AB.
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Answered by
5
yess, I can help you
In ∆AOD and ∆BOC
AD=BC ( given )
<OAD=<OBC ( all are 90° )
<AOD = <BOC ( opposite angle )
so,
by ASA congruence rule
OA = OB ( CPCT )
so, CD bisects AB
In ∆AOD and ∆BOC
AD=BC ( given )
<OAD=<OBC ( all are 90° )
<AOD = <BOC ( opposite angle )
so,
by ASA congruence rule
OA = OB ( CPCT )
so, CD bisects AB
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