Question-3 An aircraft flying at a height of 800m with uniform horizontal velocity of 360km/hr releases a
bomb which hits a target on the ground. Find (a) the time required for the bomb to reach the target, (b) the
horizontal distance of the aircraft from the target when the bomb was released (c) direction and velocity
with which the bomb hits the target.
Answers
Given : An aircraft flying at a height of 800m with uniform horizontal velocity of 360km/hr releases a
bomb which hits a target on the ground.
To Find : (a) the time required for the bomb to reach the target, (b) the
horizontal distance of the aircraft from the target when the bomb was released (c) direction and velocity
with which the bomb hits the target.
Solution:
Height = 800 m
horizontal Velocity = 360 km/hr = 360 *1000/3600 = 100 m/s
Vertical Velocity = 0 m/s
Vertical Distance = 800 m
Vertical acceleration = a = g = 9.8 m/s²
S = ut + (1/2) at²
=> 800 = (1/2)(9.8)t²
=> t² = 1600/9.8
=> t = 12.778 sec
the time required for the bomb to reach the target = 12.778 sec
Horizontal distance = horizontal Velocity x time
100 x 12.778 = 1277.8 m
horizontal distance of the aircraft from the target when the bomb was released = 1277.8 m
V = u + at = 0 + 9.8 *12.778 = 125.22 m/s
Vertical velocity = 125.22 m/s
Horizontal = 100 m/s
Net velocity = 160.25 m/s
Angle = tan⁻¹(125.22/100) = 51.39°
direction and velocity with which the bomb hits the target. 160.25 m/s at 51.39°
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