Question

Question 3 and 4 need help
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Answer 1

Answer:

3i.

x = 1/5 (4 y + 9)

3ii.

x = 2 y - 3

4i.

x = 3 - (3 y)/2

4ii.

x = 2 - (3 y)/2

Answer 2

$\large\underline{\sf{Solution-}}$

#1

Solving by submitting method:

⇝x−2y=−3−−−(ii)

By first equation,

⇝5x−4y=9

⇝5x=9+4y

⇝x=59+4y

Now, we can find the original value of y from Eqⁿ (ii).

Finding The Value of 'x'~

⇝x−2y=−3

⇝(59+4y)−2y=−3

⇝59+4y−10y=−3

⇝59−6y=−3

⇝9−6y=−3(5)

⇝9−6y=−15

⇝−6y=−15−9

⇝−6y=−6

⇝y=−6−6

⇝y=66

⇝y=1

Now, we can find the original value of x , from Eqⁿ (I)

Finding The Value Of 'x'

⇝5x−4y=9

⇝5x−4(1)=9

⇝5x−1=9

⇝5x=9+1

⇝5x=10

⇝x=510

⇝x=5

Therefore, the values of x and y are 5 and 1 respectively.

#2

Solving by Eliminating method:

⇝4x+6y=12−−−(i)

⇝6x+9y=12−−−(ii)

Step 1: Multiply Eqⁿ (I) by 3 and Eqⁿ (ii) by 2 to make the coefficients of y equal. Then we get the equations.

⇝12x+18y=36−−−(iii)

⇝12x+18y=24−−−(iv)

Step 2: Subtract Eqⁿ (iii) from Eqⁿ (iv) , we get

⇝(12x+18y)−(12x+18y)=36−24

0 =12,

Which is a false statement.

⇝0=12,

Therefore,

The pair of equations has No  Solution.

Hope this helps!!