"Question 3 Check which of the following are solutions of the equation x − 2y = 4 and which are not: (i) (0, 2 (ii) (2, 0) (iii) (4, 0) (iv) ( 2^(1/2), 4.2^(1/2) ) (v) (1, 1)
Class 9 - Math - Linear Equations in Two Variables Page 70"
Answers
Method To check whether given pair of values is a solution of given equation or not:
Sometimes a pair of values is given and we have to check whether this pair is a solution of given linear equation in two variables or not
For this we put the given values in given linear equation. If we get LHS = RHS then this pair of values is a solution of given linear equation, otherwise not.
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Solution:
i)
Given equation is
x-2y=4
On putting x=0 & y=2 in LHS
LHS= x-2y
0-2×2= -4
-4≠4
LHS ≠RHS
Hence, (0,2) is not a solution of x-2y=4
ii)
Given equation is
x-2y=4
On putting x=2 & y=0 in LHS
LHS= x-2y
2-2×0= 2
2 ≠4
LHS ≠RHS
Hence, (2,0) is not a solution of x-2y=4
iii)
Given equation is
x-2y=4
On putting x=4 & y=0 in LHS
LHS= x-2y
4-2×0= 4-0=4
4=4
LHS =RHS
Hence, (4,0) is a solution of x-2y=4
Iv)
Given equation is
x-2y=4
On putting x=√2 & y=4√2 in LHS
LHS= x-2y
√2- 2×4√2= √2-8√2=7√2
7√2≠4
LHS ≠RHS
Hence, (√2,4√2) is not a solution of x-2y=4
V)
Given equation is
x-2y=4
On putting x=1 & y=1 in LHS
LHS= x-2y
1-2×1= 1-2
-1≠4
LHS ≠RHS
Hence, (1,1) is not a solution of x-2y=4
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Hope this will help you......
Step-by-step explanation:
i)
Given equation is
x-2y=4
On putting x=0 & y=2 in LHS
LHS= x-2y
0-2×2= -4
-4≠4
LHS ≠RHS
Hence, (0,2) is not a solution of x-2y=4
ii)
Given equation is
x-2y=4
On putting x=2 & y=0 in LHS
LHS= x-2y
2-2×0= 2
2 ≠4
LHS ≠RHS
Hence, (2,0) is not a solution of x-2y=4
iii)
Given equation is
x-2y=4
On putting x=4 & y=0 in LHS
LHS= x-2y
4-2×0= 4-0=4
4=4
LHS =RHS
Hence, (4,0) is a solution of x-2y=4
Iv)
Given equation is
x-2y=4
On putting x=√2 & y=4√2 in LHS
LHS= x-2y
√2- 2×4√2= √2-8√2=7√2
7√2≠4
LHS ≠RHS
Hence, (√2,4√2) is not a solution of x-2y=4
V)
Given equation is
x-2y=4
On putting x=1 & y=1 in LHS
LHS= x-2y
1-2×1= 1-2
-1≠4
LHS ≠RHS
Hence, (1,1) is not a solution of x-2y=4
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Hope this will help you......