Question 3
Construct a ∆PQR where QR = 8 cm, ∠Q = 120° and ∠R = 30°.
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Construction of triangle PQR:
- Draw a line segment QR = 8 cm.
- From point Q, mark an angle 120°.
- Draw ray QX with this angle.
- Repeat the same step from point R but with angle 30°.
- Draw ray RY.
- QX and RY meet at a point which is the third vertex of triangle i.e, P.
- PQR is the required triangle.
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