Question

Question 3. Find a, b and c such that the following numbers are in AP
a, 7, b, 23 and c. please tell
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Answer 1

$\huge\blue{ANSWER:-}$

Since a,7,b,23,c are in AP.

∴7−a=b−7=23−b=c−23                ....(1)

On taking 2nd and 3rd expression, we get,

b−7=23−b

⇒2b=30⇒b=15

On taking 1st and 2nd expression, we get,

7−a=b−7

⇒7−a=15−7⇒a=−1

Again, on taking 3rd and 4th expression, we get,

23−b=c−23

⇒23−15=c−23⇒c=31

Hence a=−1,b=15,c=31

∴a+b+c=−1+15+31=45

Answer 2

Answer:

a=-1,b=15 and c=31

Step-by-step explanation:

Here,

a+d=7,------1

a+3d=23----2

from 1 and 2,

a + d = 7

a + 3d = 23

- - -

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-2d=-16

d=-2/-16

d=8

put this value in 1,

a+8=7

a=-1

b=a+2d

-1+2(8)=-1+16=15

b=15

Similarly,

a5=a+4d

=-1+4(8)=-1+32

c=31