Question 3 In the following figure, if LM || CB and LN || CD, prove that
Class 10 - Math - Triangles Page 128
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Hello bhaiya
answer:-
∆ABC s LM || BC
.°. AM/MB = AL/LC ( from formula )--------(1)
∆ACD s LN || CD
.°. AN/ND = AL/LC --------------(2)
From (1) and (2) we got
AM/MB = AN/ND
=> MB/AM = ND/AN
=> MB/AM + 1 = ND/AN + 1
=> MB + AM/AM = ND + AN/AN
=> AB /AM = AD/AN
=> AM/AB = AN/AD
===================================
answer:-
∆ABC s LM || BC
.°. AM/MB = AL/LC ( from formula )--------(1)
∆ACD s LN || CD
.°. AN/ND = AL/LC --------------(2)
From (1) and (2) we got
AM/MB = AN/ND
=> MB/AM = ND/AN
=> MB/AM + 1 = ND/AN + 1
=> MB + AM/AM = ND + AN/AN
=> AB /AM = AD/AN
=> AM/AB = AN/AD
===================================
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