"Question 3 In the given figure, If AB || CD, EF ⊥ CD and ∠GED = 126º, find ∠AGE, ∠GEF and ∠FGE.
Class 9 - Math - Lines and Angles Page 104"
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Alternate angles:
When two lines are crossed by another line the pair of angles on opposite sides of the transversal is called alternate angles.
Theorem 1
If a transversal intersects two Parallel Lines then each pair of alternate interior angles is equal.
Theorem 2
If a transversal intersects two lines such that a pair alternate interior angle is equal then the two lines are parallel.
Solution:
Given: ∠AGE=126°
∠AGE=∠GED=126∘
[alternate interior angles]
(ii) ∠GED=∠GEF+∠FED=126∘
⇒∠GEF+90∘=126°
(given that EF⊥CD)
⇒∠GEF=126°−90°=36°
(iii) ∠CEG+∠GED=180∘
(given ∠GED=126∘)
⇒∠CEG+126°=180∘
⇒∠CEG=180∘−126∘
⇒∠CEG=54∘
∠FGE=∠CEG=54∘
(alternate angles)
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Hope this will help you....
Answered by
16
yes
solution is here
(1) <AGE=<GED=126° ( alternate angle )
(2) <GED=126°
=> <GEF+<FED= 126°
=> <GEF + 90° = 126°
( °.° EF_|_ CD .°. <FED=90°
=> <GEF = 126°-90°=36°
(3) <GEC+<GEF+<FED= 180°
=> <GEC+36°+90°= 180°
=> <GEC=180°-126°=54°
now,
<FGE=<GEC= 54° ( alternate angle)
solution is here
(1) <AGE=<GED=126° ( alternate angle )
(2) <GED=126°
=> <GEF+<FED= 126°
=> <GEF + 90° = 126°
( °.° EF_|_ CD .°. <FED=90°
=> <GEF = 126°-90°=36°
(3) <GEC+<GEF+<FED= 180°
=> <GEC+36°+90°= 180°
=> <GEC=180°-126°=54°
now,
<FGE=<GEC= 54° ( alternate angle)
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