Question

Question 3 part 1
Solve by substitution method -
6x+15y=18 and 6x-4y+10=0

Question 4 part 2
Solve by elimination method -
-x-3y=12 and 2x-y=-3

Answer 1

Answer:

-x-3y=12(1)

2x-y=-3(2)

multiplying 3with equation (2)

6x-3y=-9(3)

-x-3y=12

6x-3y=-9

- + +

________

-7x=21

x=-3

putting the value of x in equation (1)

-x-3y=12

-(-3)-3y=12

3-3y=12

-3y=9

y=-3