Math, asked by deekshaj654, 1 month ago

Question : 3
Speed of current is 10% of speed of ship B. At 9:00
AM, ship A was 800 meter ahead of ship B, and ship
B completely crosses the ship A at 9:05 AM.
Calculate in what time ship B crosses ship C when
distance between them is 2300 meters and both are
travelling in same direction, given that sum of length
of ship B and ship A is 100 meters and speed of ship
C is same as ship A and length of ship C and ship A
is also same.​

Answers

Answered by leenamohapatra6
0

Step-by-step explanation:

It is clear from the diagram that the shortest distance between the ship A and B is PQ.

Here, Sin45

0

=

OQ

PQ

⟹PQ=100×

2

1

=50

2

m

Also,

V

AB

=

V

A

2

+V

B

2

=

10

2

+10

2

=10

2

km/h

So, the time taken to reach shortest path is

t=

V

AB

PQ

=

10

2

50

2

=5h

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