Question

Question 3
What is pH of the half cell Pt|H2 H+ if =-0.0295 V​

Answer 1

we have to find the pH of the half cell Pt|H₂(1 atom) |H⁺ , if E₀ = - 0.0295 V

solution : oxidation reaction of hydrogen is given by, (1/2)H₂⇔H⁺ + e¯

so n = 1

now using Nernst equation,

E = E₀ + 0.0591/n log [H⁺]/[H₂]½

⇒-0.0295 V = 0 + 0.0591/1 log [H⁺]/1

⇒-0.0295 × 1/0.0591 = log[H⁺]

⇒-0.4991 = log[H⁺]

⇒0.4991 = -log[H⁺] = pH [ from Arrhenius formula, pH = -log[H⁺] ]

Therefore the pH of half cell is 0.4991.

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