Question

Question:
30g of urea is dissolved in 171g of water. Calculate mole fraction of urea in solution. Molar
mass of water H2O=18g, molar mass of urea NH2CONH2 = 60g.
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Answer 1

Answer:

Mass of solution = 2.5 Kg

Molality = 0.25 m

Molar mass of urea (NH2CONH2) =(14 + 2 × 1 + 12 + 16 + 14 + 2 × 1) = 60 g mol−1

Mass of urea = Number of moles of urea × Molar mass of urea

Mass of 0.25 moles of urea = 0.25 mol × 60 g mol⁻¹ = 15 g

Mass of solution = 1000 g + 15 g = 1015 g

1015 g of aqueous solution contains urea = 15 g

∴ 2500 g of aqueous solution will require urea = 15 g / 1015 kg × 2500 g = 36.95 g = 37 g

Mass of urea required required in making 25 grams of 0.25m = 37 grams

Answer 2

Explanation:

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