Question 31:
A motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 s. What is his acceleration ?
Lakhmir Singh Physics Class 9
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given:Initial velocity = u = 0 as starting from rest
Final velocity = v = 6 m/s
Time taken in the change= t = 3 sec
thus acceleration a =( v-u)/t
⇒ acceleration =( 6-0)/3 = 2 m/s2.
Final velocity = v = 6 m/s
Time taken in the change= t = 3 sec
thus acceleration a =( v-u)/t
⇒ acceleration =( 6-0)/3 = 2 m/s2.
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ACCELERATION
..............................................................................................................✡✡✡
✡ INITIAL VELOCITY ✡ ( U ) = 0 m / s
✡ FINAL VELOCITY ✡ ( V ) = 6 m / s
✡ TIME ✡ ( T ) = 3 s
✡ ACCELERATION ✡ = V - U / T
✡ ACCELERATION ✡ = 6 - 0 / 3
✡ ACCELERATION ✡ = 6 / 3
✡ ACCELERATION ✡ = 2 m / s^2
..............................................................................................................✡✡✡
➡ HOPE IT HELPS
➡ HAVE A NICE DAY MY FRIEND
..............................................................................................................✡✡✡
✡ INITIAL VELOCITY ✡ ( U ) = 0 m / s
✡ FINAL VELOCITY ✡ ( V ) = 6 m / s
✡ TIME ✡ ( T ) = 3 s
✡ ACCELERATION ✡ = V - U / T
✡ ACCELERATION ✡ = 6 - 0 / 3
✡ ACCELERATION ✡ = 6 / 3
✡ ACCELERATION ✡ = 2 m / s^2
..............................................................................................................✡✡✡
➡ HOPE IT HELPS
➡ HAVE A NICE DAY MY FRIEND
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