Question

Question 31.
Find AD in the triangle BAC
Height=AD=?
AB=3cm
AC=4cm
BC=5cm ​

Answer 1

Answer:

triangle ABC is right triangle

3^2+4^2=5^2

9+16=25

we can use area of triangle

1/2*AD*5=1/2*3*4

AD=12/5

AD=2.4cm

Answer 2

Answer:

14.4cm^2

Step-by-step explanation:

$area = \sqrt{s(s - a)(s - b)(s - c)}$

s=a+b+c/2

=12/2=6

area^2=6(6-3)(6-4)(6-5)

=6×3×2×1

=36cm^2

ANOTHER FORMULA FOR AREA

$= 1 \div 2 \times b \times h$

=>1/2×5×h=36

=>h=36×2/5

=>h=14.4cm

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