Question

Question 33 of 50
John is traveling on his cycle and has calculated to reach point A at 2 PM if
he travel at 10 kmph he will reach there of 12 noon the travels at 15
moh At what speed must he travel to reach at 1 PM​

Answer 1

Answer:

Let the distance travelled by x km.

Then, 10x−15x=2

⇒3x−2x=60

⇒x=60km.

Time taken to travel 60 km at 10 km/hr = (1060)hrs = 6 hrs.

So, John started 6 hours before 2 P.M. i.e., at 8 A.M.

∴ Required speed =(560)kmph. = 12 kmph.

Answer 2

Explanation:

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