Question 33.....rs agrawal
Answers
Step-by-step explanation:
L.C.M of 48, 72, 108 = 2 x 2 x 2 x 2 x 3 x 3 x 3 = 432 sec.
After 432 seconds, the lights change simultaneously.
432 second = 7 minutes 12 seconds
Therefore the time = 7 a.m. + 7 minutes 12 seconds
= 7:07:12 a.m.
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MATHS
The traffic lights at three different road crossing change after every 48 seconds, 72 seconds and 108 seconds respectively.If they change simultaneously at 7 : 00 a.m, at what time will they change simultaneously again?
December 20, 2019Sharvari Modak
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ANSWER
Consider the problem
The traffic light at three different road crossing change after every 48seconds,72seconds and 108seconds respectively
So,
48=2×2×2×2×372=2×2×2×3×3108=2×2×3×3×3
Therefore, L.CM of 48,72,108 is
(2×2×2×2×3×3×3)=432
So, time when they change again =432seconds
But we need to find time after 7am So, first we convert 432seconds into minutes.
Time=432second=60432minutes∴Time=7 minutes12 seconds
Thus,
Required time =7am+7minutes 12seconds
=7:07:12am
Hope it will help you