Question

Question 34 Of R. D. Sharma chapter 15 of revision exercise

Answer 1

Area of section=x/360×Πr²

Area of S1= 120/360×Πr².....(1)
and, Area of S2=150/360×Πr²......(2)
Divinding (1) by (2) we get,

120/360×Πr²
___________
150/360×Πr²

= 120/360
__________
150/360

= 120/150
= 12/15 =4/5
Therefore ratio = 4:5