Math, asked by Royal31, 1 year ago

Question...............

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Answered by sk0768173gmailcom

cosA/1-sinA/cosA+sinA/1-cosA/sinA
=cos2A/cosA-sinA --sin2A/cosA-SinA
=cos2A-sin2A/cosA-sinA
=cosA+sinA Option B ans

Answered by umakant7

B is the answer sin A+cos A

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umakant7: same as first function second function became sin^2A/sinA-cosA

Royal31: I m talking about the second last step

umakant7: first take -from the denomination of seconds function so that it can be easy to take lcm between two function and after lcm break the above function and cut the similar part and u we get ur answer

Royal31: But y its still cosA - sinA in the denominator after the lcm

Royal31: Y not square

umakant7: the denominator is same so we will not square for example 1/2+2/2=(1+2)/2

Royal31: Okay

Royal31: Thank you so much....

umakant7: lcm of example is 2 u can see it because in both the function denominator is 2

umakant7: it my pleasure

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