Question

Question 36
A particle is moving along a straight line with uniform retardation of 2ms. The initial speed of particle is 20m/s. The
distance travelled by the particle during the last one second before it stops is

Answer 1

Answer:

The distance travelled in n

th

second is

S

n

=u+

2

1

(2n−1)a ....(1)

So distance travelled in t

th

&(t+1)

th

second are

S

t

=u+

2

1

(2t−1)a ....(2)

S

t+1

=u+

2

1

(2t+1)a ....(3)

As per question,

S

t

+S

t+1

=100=2(u+at) ....(4)

Now from first equation of motion the velocity of particle after time t, if it moves with an acceleration a is

v=u+at ....(5)

where u is initial velocity

So from equation (4) and (5), we get v=50cm/s

Answer 2

ur ans is in above attachment ☺☺☺

hope it helps u....❤