Question.3A stone is thrown in a vertically upward direction with a velocity of 5 ms~1. If the acceleration of the stone during its motion is 10 ms~2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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Answer:
Given, initial velocity, u=5ms
−1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms
−2
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v
2−u 2 =2as, we have
s=v2−u 2/2a
=(0)
2−(5) 2
/2×(−10)=1.25m
(ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5s
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