Question

Question.3A stone is thrown in a vertically upward direction with a velocity of 5 ms~1. If the acceleration of the stone during its motion is 10 ms~2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?​

Answer 1

Answer:

Given, initial velocity, u=5ms

−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms

−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v

2−u 2 =2as, we have

s=v2−u 2/2a

=(0)

2−(5) 2

/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s