Question 4.18 An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.
Chapter Motion In A Plane Page 87
Answers
Answered by
22
Radius of horizontal loop executes by aircraft is 1 km or 1000 m
Speed of aircraft = 900 km/h
= 900× 5/18 m/s
= 250 m/s
Centripital accⁿ = v²/r
= (250)²/1000
= 62500/1000
= 62.5 m/s²
We know,
accⁿ due to gravity=9.8m/s²
So, centripital accⁿ/accⁿ due to gravity = 62.5/9.8 = 6.38
Speed of aircraft = 900 km/h
= 900× 5/18 m/s
= 250 m/s
Centripital accⁿ = v²/r
= (250)²/1000
= 62500/1000
= 62.5 m/s²
We know,
accⁿ due to gravity=9.8m/s²
So, centripital accⁿ/accⁿ due to gravity = 62.5/9.8 = 6.38
Answered by
4
==============ⓢⓦⓘⓖⓨ
==============ⓢⓦⓘⓖⓨ
Radius of the loop, r = 1 km = 1000 m
Speed of the aircraft,
v = 900 km/h= 900× 5/18 = 260m/s
Centripetal acceleration,
a(c) = v^2/ r
= (250)^2/1000
= 62.5 m/s^2
Acceleration due to gravity, g = 9.8 m/s2
a(c)/ g
=62.5/9.8
= 6.38
=> a(c)= 9.38 g
I hope, this will help you
=======================
·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·
___________♦♦⭐♦ ♦___________
Similar questions
Biology,
8 months ago
Physics,
1 year ago
Physics,
1 year ago
History,
1 year ago
Social Sciences,
1 year ago