Physics, asked by BrainlyHelper, 1 year ago

Question 4.18 An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.

Chapter Motion In A Plane Page 87

Answers

Answered by abhi178
22
Radius of horizontal loop executes by aircraft is 1 km or 1000 m

Speed of aircraft = 900 km/h
= 900× 5/18 m/s
= 250 m/s

Centripital accⁿ = v²/r
= (250)²/1000
= 62500/1000
= 62.5 m/s²

We know,
accⁿ due to gravity=9.8m/s²
So, centripital accⁿ/accⁿ due to gravity = 62.5/9.8 = 6.38
Answered by Anonymous
4

==============ⓢⓦⓘⓖⓨ

\huge\mathfrak\red{hello...frd\:swigy\:here}

==============ⓢⓦⓘⓖⓨ

Radius of the loop, r = 1 km = 1000 m

Speed of the aircraft,

v = 900 km/h= 900× 5/18 = 260m/s

Centripetal acceleration,

a(c) = v^2/ r

= (250)^2/1000

= 62.5 m/s^2

Acceleration due to gravity, g = 9.8 m/s2

a(c)/ g

=62.5/9.8

= 6.38

=> a(c)= 9.38 g

I hope, this will help you

=======================

<marquee behaviour-move bigcolour-pink><h1>☺ThankYou✌</h1></marquee>

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________

Similar questions