Question 4.8 Although geometries of NH3 and H2O molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.
Class XI Chemical Bonding and Molecular Structure Page 130
Answers
Answered by
183
concept : the size of lone pair is larger than bond pair .it means more the number of lone pair of electrons , lesser the bond angle .
Here, In H2O molecule , there is one lone pair -lone pair repulsion because the presence of two lone pairs of electrons . while in NH3 molecule , there are only one lone pair - bond pair repulsion .
now, According to VSEPR theory ,
lp - bp is more stronger ( stable ) than lp - lp. so, the second one is more stronger .hence, bond angle of water is less than bond angle of ammonia.
in simple way, you can say that bond angle of H2O is lesser due to number of lone pair is more.
Here, In H2O molecule , there is one lone pair -lone pair repulsion because the presence of two lone pairs of electrons . while in NH3 molecule , there are only one lone pair - bond pair repulsion .
now, According to VSEPR theory ,
lp - bp is more stronger ( stable ) than lp - lp. so, the second one is more stronger .hence, bond angle of water is less than bond angle of ammonia.
in simple way, you can say that bond angle of H2O is lesser due to number of lone pair is more.
Attachments:
Answered by
61
Answer:
Since the repulsions on the bond pairs in H2O molecule are greater than that in NH3, the bond angle in water is less than that of ammonia. Although geometry of NH3 and H2O molecules are distorted tetrahedral, bond angle in water is less than that of ammonia.
Explanation:
Similar questions