Question

question 4.a part plz answer fast ​

Answer 1

Answer:

Step-by-step explanation:let the total expression be equals to k

3Log4/3log5-log10=k

Log4/log5-1=I

X=2 and y=2

Answer 2

$\huge \sf {\red{\underline {\blue {\underline {A᭄ɴsᴡᴇʀ࿐ \ :- }}}}}$

$\huge{ \underline{ \bf{Given \: : }}}$

• Length of the rectangle hall is 4 metres more than its breadth

• perimeter of the hall is 56 meters

$\huge{ \underline{ \bf{To \: Find \: : }}}$

• Length and breadth

$\huge{ \underline{ \bf{Solution \: : - }}}$

Let the breadth of the hall be x

And let the length of the hall be

x + 4

As we know,

Perimeter of a rectangle

$\red{ \underline{ \underline{ \boxed{ \tt{ \green{Perimeter = 2(length + breadth)}}}}}}$

$\tt \to56 =2(x + (x + 4))$

$\tt \to \cancel \frac{56}{2} = x + x + 4$

$\tt \to28 = 2x + 4$

$\tt \to2x = 28 - 4$

$\tt \to2x = 24$

$\tt \to \: x = \cancel \frac{24}{2}$

$\tt \to \: x = 12$

Therefore,

Breadth = 12m

Length = (x + 4) = 12 + 4 = 16m