Question

Question 4
A particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of 2.5m/s2. Find the displacement in the next 4 sec.?m​

Answer 1

Answer:

Explanation:

Correct Question :-

A particle moving with an initial velocity of 5 m/s is subjected to a uniform acceleration of 2.5 m/s². find the displacement in the next 4 second.

Answer :-

Given :-

u = 5 m/s

a = 2.5 m/s²

t = 4 seconds

Formula to be used :-

Third Equation i.e s = ut + at²/2

Solution :-

Putting the values, we get

s = ut + at²/2

⇒ s = 5 × 4 + 2.5 × 4²/2

⇒ s = 20 + 20

⇒ s = 40 m

Hence, the displacement in the next 4 sec is 40 m.

Answer 2

Answer:

$\frak{Given}\begin{cases}\sf{Initial \:Velocity \: (u) = 5 \:m/s}\\\sf{Acceleration \:(a) = 2.5 \: m/s^2}\\\textsf{Time (t) = 4 sec}\end{cases}$

$\rule{120}{1}$

$\boxed{\bf{\mid{\overline{\underline{\bigstar\: Using\: Second\: Equation\:of\: Motion :}}}}\mid}$

$:\implies\sf S=ut+{}^{1}\!/{}_{2}at^2\\\\\\:\implies\sf S=(5 \times 4)+\bigg\lgroup{}^{1}\!/{}_{2} \times2.5 \times (4)^2\bigg\rgroup\\\\\\:\implies\sf S = 20 + \bigg\lgroup{}^{1}\!/{}_{2} \times2.5 \times 16\bigg\rgroup\\\\\\:\implies\sf S = 20 + \bigg\lgroup2.5 \times 8\bigg\rgroup\\\\\\:\implies\sf S = 20 + 20\\\\\\:\implies\underline{\boxed{\sf S = 40 \:metre}}$

⠀

$\therefore\:\underline{\textsf{Displacement in next 4 sec. is \textbf{40 metre}}}.$