Question

Question 4
(a) The population of a town increases by 6% annually. If the present population is 17,490,
what was it a year ago​

Answer 1

Answer:

Step-by-step explanation:

It is very simple question

Answer 2

QUESTION The population of a town increases by 6% annually. If the present population is 17,490,

what was it a year ago?

Solution

Given : Present value = 17490

increase in population = 6% .

To find : population before 1 year .

If it increases 6% every year means it was 6% less a year ago .

formula for depreciation :

$p(1 - \frac{r}{100} ) {}^{time} \\ = > 17490( \frac{1 - 6}{100} ) {}^{1} \\ = > 17490( \frac{100 - 6}{100} ) {}^{1} \\ = > 17490( \frac{94}{100} ) {}^{1} \\ = > 17490( \frac{47}{50} ) {}^{1} \\ = > (1749 \frac{47}{5} ) {}^{1} \\ = > ( \frac{82203}{5} ) {}^{1} \\ = > 16440.60$

Answer :

16440.60