Question

Question 4
a) The sum of two positive numbers is 11 and the sum of their squares is
65. Find:
1. The difference between their squares.
The sum of their cubes.​

Answer 1

Answer:

let the first no is x

So the second no is (11-x)

According to question

x^2+(11-x)^2=65

x^2+121+x^2-22x=65

2x^2-22x+56=0

divide the equation by 2

x^2-11x+28=0

x^2-7x-4x+28=0

x(x-7)-4(x-7)=0

(x-7)(x-4)=0

(x-7)=0

x=7

(x-4)=0

x=4

So the No are 4 and 7

Step-by-step explanation:

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