Question-4: Aball of mass 0.01kg is moving with a velocity for 2 seconds on the
ball, it acquires a velocity of 70m/sec. Calculate the initial and final momentum of
the ball. Also, calculate the rate of change of momentum and acceleration of the
ball. What would be the magnitude of the force applied?
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Answer:
Given -
m = 0.01 kg
u = 50 m/s
t = 2 sec
v = 70 m/s
where
v is final velocity
u is initial velocity
t is time
m is mass of ball.
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To find -
1.
2.
3.
4. a
5. f
where
is initial momentum.
is final momentum.
a is acceleration.
f is magnitude of force.
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Formula used -
where
p is momentum.
m is mass.
v is velocity.
u is initial velocity.
a is acceleration.
t is time.
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Solution -
1.
m = 0.01 kg
u = 50 m/s
= 0.01 × 50
Initial momentum = 0.5 kg m/s
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2.
m = 0.01 kg
v = 70 m/s
= 0.01 × 70
Final momentum = 0.7 kg m/s
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3.
= 0.7 - 0.5 = 0.2 kg m/s
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4.
v = 70 m/s
u = 50 m/s
t = 2sec
70 = 50 + 2a
20 = 2a
a = 10 m/s²
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5.
a = 10 m/s²
m = 0.01 kg
F = 10 × 0.01
F = 0.1 N
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Thanks
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