Question

Question 4 In a certain lottery, 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets?

Class X1 - Maths -Probability Page 409

Answer 1

( a) 1 ticket out of 10,000 tickets can be selected n( S ) = ¹⁰⁰⁰⁰C₁

A/C to question,
10 tickets equal prizes are awarded .so, number of tickets without any prize = 10,000 - 10 = 9,990
so, number of ways in which 1 ticket without prize is obtained n( E ) = ⁹⁹⁹⁰C₁

so, P ( E ) = n ( E )/n( S )
=⁹⁹⁹⁰C₁ / ¹⁰⁰⁰⁰C₁
= 9,990/10,000
= 999/1000
= 0.999

similarly ,
( b ) 2 tickets out of 10,000 can be selected n( S ) = ¹⁰⁰⁰⁰C₂
2 ticket without prize out of 9,990 = ⁹⁹⁹⁰C₂
so, P(E ) = n(E )/n(S )
= ⁹⁹⁹⁰C₂ / ¹⁰⁰⁰⁰C₂


(c ) 10 tickets out of 10,000 can be selected n(S) = ¹⁰⁰⁰⁰C₁₀
10 tickets without prize out of 9,990 can be selected = ⁹⁹⁹⁰C₁₀
so, P( E ) = n(E)/n(S )
= ⁹⁹⁹⁰C₁₀ / ¹⁰⁰⁰⁰C₁₀

Answer 2

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