Math, asked by Dhru016, 10 months ago

question 4
plz answer​

Attachments:

Answers

Answered by rosh16
1
angle BOP+ angle POA=180 degree
115+angle POA=180
angle POA=65 degrees
in triangle POA
angle APO+angle PAO+ angle POA=180
angle APO+65+ 90=180
angle APO+155=180
angle APO=25 degrees
pls mark this as the brainliest answer

Dhru016: hey
Dhru016: thank you
Answered by geetuk321
1

∠PAO = 90°  (Line joining point contact and centre of circle)

∠AOP + ∠POB = 180°  (linear pair)

∠AOP + 115° = 180°

∠AOP = 65°

∠AOP + ∠PAO +∠APO = 180° (angle sum property of triangle)

∠APO = 180° -90° -65°

∠APO = 25°

Hope this helps you..

Similar questions