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Question 4
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Pls prove it
#mathsmarties
10 POINTS!!!!!!

Thank you♡

Answer 1

To prove -AD/DG=CF/FG
DFG~ACG

Proof- DE//AB
GD/AD=GE/BE
AD/GD=BE/GE

EF//BC
GE/BE=GF/FC
BE/GE=FC/GF

AD/DG=FC/GF




IN triangle DFG and ACG
angle G = angle G (common)
angle GDF= angle GAC (corresponding angles)
DFG~ACG(AA)



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Answer 2

A)

Given- AB||DE and BC||EF

To prove - 1) AD/DG = CF/FG

2) DFG ~ ACG

Proof- in ∆ABG

DE||AB

So DG/AD=GE/EB--(1). ( by BPT)

In∆BCG

EF||BC

So FG/CF=GE/EB--(2). (by BPT)

By eq(1) And eq(2)

DG/AD =FG/CF

AD/DG=CF/FG--- hence prove

Thus DF||AC

In ∆ DFG and ∆ ACG

angle G = angle G (common)

angle FDG = angle CAG (corresponding angles)

So, by AA

∆DFG ~ ∆ACG---- hence prove

Hope it helps....