Physics, asked by Atharvnnema, 9 months ago

QUESTION 4 = THE PRESENT AGE OF SAHIL'S MOTHER IS THREE TIMES
THE PRESENT AGE OF SAHIL. AFTER 5 YEARS THEIR AGES WILL ADD TO
66 YEARS. FIND THEIR PRESENT AGES.​

Answers

Answered by rk84678010
0

Answer:

Let the present age of Sahil be x,sahil's mother age be 3x.5years later sahil's age is x+5,sahil's mother's age is 3x+5.sum if their ages after 5years is 4x+10.

4x+10=66

4x=66-10

x=56÷4

x=14.

sahil's present age is 14& sahil's mothers age is 3×14=42 years.

after 5 years

sahil's age is 14+5=19

sahil's mother age is 42+5=47

19+42=66years

Answered by patel444414
0

ANSWER

Let present age of Sahil =x years

Let present age of Sahil's mother =y years

The present age of Sahil's mother is three times the present age of Sahil.

So,

y=3x ......... (1)

After 5 years their ages add to 66 years.

After 5 years Sahil age =x+5

After 5 years Sahil's mother age =y+5

Now,

x+5+y+5=66

x+y+10=66

x+y=66−10

x+y=56 ......... (2)

From (1) and (2),

x+3x=56

4x=56

x=14 years

From (1),

y=3x

=3(14)

=42 years

present age of Sahil =14 years

present age of Sahil's mother =42 years

Hope this helps you

All the best.

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