question 43 please explain.......
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since (a+b+c)^2 = a^2 +b^2 +c^2 +2ab +2bc +2ca
and also (a+b-c)^2= a^2+b^2+c^2+2ab- 2bc- 2ca
2( c^2-a^2-b^2-2ab)= 2c^2- 2a^2- 2b^2 -4ab
so insert these values inside the root cancel the positive and negtive terms.
we get answer 0.
and also (a+b-c)^2= a^2+b^2+c^2+2ab- 2bc- 2ca
2( c^2-a^2-b^2-2ab)= 2c^2- 2a^2- 2b^2 -4ab
so insert these values inside the root cancel the positive and negtive terms.
we get answer 0.
Theodric:
gr8 thnx vry much....
welcome.hope it helped
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