Question

Question 47
A number when successively divided by 3, 5 and 7 respectively
leaves remainders 1, 3, 1. Find the successive remainders when it is
divided by 7, 5 and 3.​

Answer 1

Step-by-step explanation:

When a number is being successively divided by 3,5 and 8 leaving the remainder 1,4 and 7 respectively ,let the last quotient be x. Then the previous quotient is 8x+7 and the previous quotient to this one is 5(8x+7)+4= 40x+39. So the number is 3(40x+39)+1=120x+118. 120 is divisible by 3,5 and 8