Question

Question 5.12 Calculate the temperature of 4.0 mol of a gas occupying 5 dm^3 at 3.32 bar.

(R = 0.083 bar dm^3 K–1 mol–1).

Class XI States of Matter Page 153

Answer 1

Apply ideal gas equation ,
PV = nRT
here, P = 3.32 bar
V = 5 dm³
n = 4 mol
R = 0.083 bar dm³/K/mol
T = ?

now, PV = nRT
T = PV/nR
=3.32 bar × 5 dm³ /4 mol × 0.083 bar dm³/K/mol
= 50 K

hence, Temperature = 50K