Question

Question 5.19 A shell of mass 0.020 kg is fired by a gun of mass 100 kg. If the muzzle speed of the shell is 80 m s–1, what is the recoil speed of the gun?

Chapter Laws Of Motion Page 111

Answer 1

Mass of shell = 0.02 Kg
Mass of Gun = 100 Kg
Muzzle speed of the shell = 80m/s

External force acts equal to zero.
So, according to law of conservation of linear momentum
Pi = Pf
Gun and shell both are at rest initially . hence, Pi = 0 .
Let fnally recoil speed of Gun = V
Pf = mv + MV

Pi = Pf
0 = mv + MV
V = - (m/M)v
= -(0.02/100)×80m/s
= -0.016 m/s
Hence, recoil speed = 0.016m/s

Answer 2

☺Hello friend____❤

✒Your answer is here⤵

Mass of the gun, M = 100 kg

Mass of the shell, m = 0.020 kg

Muzzle speed of the shell, v = 80 m/s

Recoil speed of the gun = V

Both the gun and the shell are at rest initially.

Initial momentum of the system = 0

Final momentum of the system = mv – MV

Here, the negative sign appears because the directions of the shell and the gun are opposite to each other.

According to the law of conservation of momentum:

Final momentum = Initial momentum

mv – MV = 0

V = mv/M = ( 0.020× 80)/(100× 1000)

= 0.016 m/s

I hope, this will help you

Thank you_____❤

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