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Question 5.31 A train runs along an unbanked circular track of radius 30 m at a speed of 54 km/h. The mass of the train is 106 kg. What provides the centripetal force required for this purpose – The engine or the rails? What is the angle of banking required to prevent wearing out of the rail?

Chapter Laws Of Motion Page 112

Answers

Answered by Anonymous
27
Hi__
hope u know
angle of bank formulas
it is
tanQ=(velocity)^2/ radius x acceleration

use this we get
Q=36.87 degree
hope it help
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Answered by abhi178
20
the centripetal force required by the train to cross the circular bend is provided by the lateral thrust exerted by the outer rails on the wheels .
According to Newton's law train also exert equal and opposite direction force on the rails causing it wear and tear .

speed of train = 54 km/h
= 54 *5/18 m/s
= 15 m/s
radius of ciruclar bend = 30 m
mass of train = 10^6 kg

Let train inclined {theta} angle with vertical shown in figure .
in equilibrium ,
vertical components :
Ncos {theta} = mg -----------(1)
Nsin {theta} = mv^2/r ---------(2)
divide (2) and (1)
tan {theta} = v^2/rg
= (15)^2/(30)(10)
= 3/4
tan {theta} = 3/4
{theta} = tan^-1 {3/4}
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