Question

Question 5.4 One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:

(i) T,
(ii) T-((mv^2) / l),
(iii) T+((mv^2) / l),
(iv) 0

T is the tension in the string. [Choose the correct alternative].

Chapter Laws Of Motion Page 110

Answer 1

We know,
When , a particle tied with sting and moves in circular , the required centripital force = tension in string

Here length of string 'l ' is connected to a particle of mass m . after moving of string in a circle with speed v.
Centripital force = mv²/l directed towards the centre . and tension in string is T
Hence, net Force of string
directed towards centre = centripital force = Tension in string
e.g T = mv²/l
hence , correct alternative is T

Answer 2

Answer:

T

Explanation:

iT is the correct answer.

A particle connected to a string is revolving in a circular

orbit around the center.

For rotation, the centripetal force is provided by the

tension produced in the string.

Therefore, the net force produced on the particle is the

tension, T.

That is,

F = T = mv square by l

where,

F is the net force acting on the particle.