Question 5.7 A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.
Chapter Laws Of Motion Page 110
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Answered by
300
8N and 6N forces are acted perpendicularly on a body of mass 5kg .
We know,
We two foce F1 and F2 are perpendicular then ,
Net Force = √(F1² + F2²)
Use this concept here,
Here, F1 = 8 N
F2 = 6N
Fnet = √(8² + 6²) N
= √(64 + 36) N
= 10 N
Let net Force makes ∅ with 6N ,
Then, tan∅ = F1/F2
Tan∅ = 8/6 = 4/3
∅ = tan-¹(4/3)
We know,
We two foce F1 and F2 are perpendicular then ,
Net Force = √(F1² + F2²)
Use this concept here,
Here, F1 = 8 N
F2 = 6N
Fnet = √(8² + 6²) N
= √(64 + 36) N
= 10 N
Let net Force makes ∅ with 6N ,
Then, tan∅ = F1/F2
Tan∅ = 8/6 = 4/3
∅ = tan-¹(4/3)
Answered by
31
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