Science, asked by Rishabhsingh30, 5 hours ago

دارا
Question 5
An object of height 1 mm is kept 60 cm.
away from a concave lens of focal length 40
cm. then height of image will be
Only one option is correct
A
O
0.4 mm
B
O
2.4 mm
С
O
0.5 mm
D
О
0.6 mm
MARK FOR REVIEW​

Answers

Answered by nohgtcghjbhik
0

Answer:

Isbsisenenje9eebee8ebeebe nnijndmddlsldndo nnsjss ssospsmsossjso knddbhdh jsbdeieneekeosnwowkweneiej ksbejeebkeemmsslsk kenejeeieheboesns

Answered by aliyasubeer
3

Answer:

Height of image will be 0.4mm

Explanation:

Given: height of object h₀=1x10⁻² cm

hi+ height of image=?

focal length f=-40cm

distance between object and lens u= - 60cm

Using lens formula,

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$$\frac{1}{v}+\frac{1}{(-60)}=\frac{1}{(-40)}$\\$\frac{1}{v}=\frac{-1}{40}+\frac{1}{-60}$$\frac{1}{v}=\frac{100}{2400}$$v=-24 \mathrm{~cm}$\\\\\

The image will be formed 24cm in front of the lens.

magnification m=\frac{h_{i} }{h_{o} } =-(\frac{v}{u} )

\frac{h_{i} }{.01} =-(\frac{-24}{-60} )\\\\h_{i} =-(\frac{-24}{-60} )*.01\\         =.004cm=0.4mm

Similar questions