Question

دارا
Question 5
An object of height 1 mm is kept 60 cm.
away from a concave lens of focal length 40
cm. then height of image will be
Only one option is correct
A
O
0.4 mm
B
O
2.4 mm
С
O
0.5 mm
D
О
0.6 mm
MARK FOR REVIEW​

Answer 1

Answer:

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Answer 2

Answer:

Height of image will be 0.4mm

Explanation:

Given: height of object h₀=1x10⁻² cm

hi+ height of image=?

focal length f=-40cm

distance between object and lens u= - 60cm

Using lens formula,

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f} \frac{1}{v}+\frac{1}{(-60)}=\frac{1}{(-40)} \\ \frac{1}{v}=\frac{-1}{40}+\frac{1}{-60} \frac{1}{v}=\frac{100}{2400} v=-24 \mathrm{~cm}$

The image will be formed 24cm in front of the lens.

magnification $m=\frac{h_{i} }{h_{o} } =-(\frac{v}{u} )$

$\frac{h_{i} }{.01} =-(\frac{-24}{-60} )\\\\h_{i} =-(\frac{-24}{-60} )*.01\\ =.004cm=0.4mm$