Question 5 An organization selected 2400 families at random and surveyed them to determine a relationship between income level and the number of vehicles in a family. The information gathered is listed in the table below:
Monthly Income (in Rs) Vehicles per family
0 1 2 Above 2
Less than 7000 10 160 25 0
7000-10000 0 305 27 2
10000-13000 1 535 29 1
13000-16000 2 469 59 25
16000 or more 1 579 82 88
Suppose a family is chosen, find the probability that the family chosen is
(i) earning Rs 10000 − 13000 per month and owning exactly 2 vehicles.
(ii) earning Rs 16000 or more per month and owning exactly 1 vehicle.
(iii) earning less than Rs 7000 per month and does not own any vehicle.
(iv) earning Rs 13000 − 16000 per month and owning more than 2 vehicles.
(v) owning not more than 1 vehicle.
Class 9 - Math - Probability Page 283"
Answers
Answered by
196
Probability is the study of the chances of events happening.
Event:
A Possible outcome or combination of outcomes is called event.
The probability of happening our event always lies from 0 to 1.
The sum of all the probabilities of all possible outcomes of an experiment is 1.
Required probability=number of trials in which the event E has happened/Total number of trials
_________________________
Solution:
Total numbers of families selected by the organisation to Survey= 2400.
i) Let E1 be the event of choosing of family earning ₹(10000 -13000) per month and owning exactly two vehicles.
Numbers of families earning ₹10000 –13000 per month and owning exactly 2 vehicles = 29
Required probability P(E1) = 29/2400
ii) Let E2 be the event of choosing of family earning ₹16000 or more per month and owning exactly 1 vehicle.
Number of families earning ₹16000 or more per month and owning exactly 1 vehicle = 579
Required probability,P(E2) = 579/2400
(iii)
Let E3 be the event of choosing of family earning than ₹ 7000 per month and does not own any vehicle.
Number of families earning less than ₹7000 per month and does not own any vehicle = 10
Required probability ,P(E3)= 10/2400 = 1/240
iv) Let E4 be the event of choosing a family earning ₹(13000 -16000) per month and owning more than 2 vehicles.
Number of families earning ₹13000-16000 per month and owning more than 2 vehicles = 25
Required probability,P(E4) = 25/2400 = 1/96
(v) Let E5 be the event of choosing a family owning not more than 1 vehicle.
Number of families owning not more than 1 vehicle i.e. the number of families owning 0 vehicle and 1 vehicle= 10+160+0+305+1+535+2+469+1+579
= 2062
Required probability,P(E5) = 2062/2400 = 1031/1200
========================================
Hope this will help you....
Event:
A Possible outcome or combination of outcomes is called event.
The probability of happening our event always lies from 0 to 1.
The sum of all the probabilities of all possible outcomes of an experiment is 1.
Required probability=number of trials in which the event E has happened/Total number of trials
_________________________
Solution:
Total numbers of families selected by the organisation to Survey= 2400.
i) Let E1 be the event of choosing of family earning ₹(10000 -13000) per month and owning exactly two vehicles.
Numbers of families earning ₹10000 –13000 per month and owning exactly 2 vehicles = 29
Required probability P(E1) = 29/2400
ii) Let E2 be the event of choosing of family earning ₹16000 or more per month and owning exactly 1 vehicle.
Number of families earning ₹16000 or more per month and owning exactly 1 vehicle = 579
Required probability,P(E2) = 579/2400
(iii)
Let E3 be the event of choosing of family earning than ₹ 7000 per month and does not own any vehicle.
Number of families earning less than ₹7000 per month and does not own any vehicle = 10
Required probability ,P(E3)= 10/2400 = 1/240
iv) Let E4 be the event of choosing a family earning ₹(13000 -16000) per month and owning more than 2 vehicles.
Number of families earning ₹13000-16000 per month and owning more than 2 vehicles = 25
Required probability,P(E4) = 25/2400 = 1/96
(v) Let E5 be the event of choosing a family owning not more than 1 vehicle.
Number of families owning not more than 1 vehicle i.e. the number of families owning 0 vehicle and 1 vehicle= 10+160+0+305+1+535+2+469+1+579
= 2062
Required probability,P(E5) = 2062/2400 = 1031/1200
========================================
Hope this will help you....
Answered by
57
Answer:
(1) 9 by 800 (2) 193 by 800 (3) 1 by 240 (4) 7 by 200 (5) 1031 by 1200 is correct answer plz try to solve itself...... okay
Similar questions