Question

Question 5. Calculate the work done by a girl weighing 55 kg is climbing
up a hill 1500 m high (g = 9.8 m/s )​

Answer 1

Given:-

☛Girl's weight = 55kg

☛Climbing high (height) = 1500m

Find:-

☛Work done-?

Formula to be used:-

☛W= m×g×h

where,

W= work done,

m= mass

g= acceleration due to gravity

h= height

Solution:-

☛When force is exerted on body and body is displaced, it is said to be work done.

Work = Force x Displacement

Or,

W = F x s

Where, W is work

‘F’ is force and    ‘s’ is displacement.

F= ma

therefore,

W= m×g×h

Put the value in the formula we get,

$\sf{\implies W= 55\times 1500\times 9.8}$

$\sf{\implies W= 808500}$

$\bf{ W= 8085 \times 10^2}$

$\bf{\underline{\pink{\therefore, work \ done \ by \ girl \ is \ 8085 \times 10^2 }}}$.

Answer 2

$\sf \star \huge \: { \underline{Given : }} \\ \\ \\ </p><p></p><p> \sf \bullet \large\: a \: girl \: weight \: is \: 55 \: kg \\ \\ </p><p> \sf \bullet \large \: height \: = \: 1500 \: m </p><p> \: \\ \\ \sf \bullet \large gravity \: due \: to \: acceleration= 9.8 \: m/s \\ \\ \\ </p><p></p><p></p><p> \sf \star \huge \: { \underline{To \: Find}} \\ \\ \\ </p><p></p><p>\sf \bullet \large \: Work \: Done \\ \\ \\ </p><p></p><p>\sf \star \huge \: { \underline{Formula}} \\ \\ </p><p></p><p>\sf \bullet \large \: Work \: done = m \times g \times h \\ \\ </p><p></p><p>\sf \bullet \large \: where , </p><p>\sf \bullet \large \: m = mass \: of \: the \: body \\ </p><p>\sf \bullet \large \: g = gravity \: due \: to \: acceleration \\ </p><p>\sf \bullet \large \: h = \: height \\ \\ \\ \\ \\ \\ </p><p></p><p>\sf \star \huge \: { \underline{Solution :}} \\ \\ \\ \sf \implies \large \: work \: done \: = m \: \times g \: \times h \: \\ \\ \sf \implies \large \: work \: done \: = 55 \times 1500 \times 9.8 \\ \\ \sf \implies \large \: work \: done = 82500 \times 9.8 \\ \\ \sf \implies \large \: work \: done = 808500 \: joule \\ \\ \\ \\ \therefore \sf { \boxed{ \underline{ \red{ \bold{work \: done = 808500 \: joule}}}}}$