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Question 5: Differentiate the following w.r.t. x: log (cos e^x)

Class 12 - Math - Continuity and Differentiability

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Answered by Anonymous
6
Refer to the attachment
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Answered by Anonymous
5
★ DIFFERENTIATION ★

Given function :

log ( Cos e^x )

dy ( log e^x )/dx =

1/ Cos e^x [ dy/dx of Cos e^x ]

dy ( Cos e^x )/dx = - Sin e^x ( e^x )

Now combining the respective equivalents ,

dy/dx = -e^x Sin e^x / Cos e^x

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